What are the solutions to the equation m^2-12m+23=5 ?

The solutions to the equation m^2-12m+23=5 are m=3(2+sqrt(2)),m=3(2-sqrt(2))

Find the zeros of m^2-12m+23=5

The zeros of m^2-12m+23=5 are m=3(2+sqrt(2)),m=3(2-sqrt(2))

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m^{2} - 12 m + 23 = 5

m = 3 (2 + 2), m = 3 (2 - 2)

Decimal Notation

m = 10.24264 \dots, m = 1.75735 \dots

Solution steps

m^{2} - 12 m + 23 = 5

Move

5

to the left side

m^{2} - 12 m + 18 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 18 = 62

m_{1, 2} = \frac{- ( - 12 ) \pm 6 2}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 12 ) + 6 2}{2 \cdot 1}, m_{2} = \frac{- ( - 12 ) - 6 2}{2 \cdot 1}

m = \frac{- ( - 12 ) + 6 2}{2 \cdot 1} : 3 (2 + 2)

m = \frac{- ( - 12 ) - 6 2}{2 \cdot 1} : 3 (2 - 2)

The solutions to the quadratic equation are:

m = 3 (2 + 2), m = 3 (2 - 2)

1 - \frac{( 2 - x )}{3} = 2

\frac{81}{100}

8 x - 3 x \leq 10

x^{2} - 16 x + 63

∣ x - 2 ∣ > - 2

What are the solutions to the equation m^2-12m+23=5 ?
The solutions to the equation m^2-12m+23=5 are m=3(2+sqrt(2)),m=3(2-sqrt(2))
Find the zeros of m^2-12m+23=5
The zeros of m^2-12m+23=5 are m=3(2+sqrt(2)),m=3(2-sqrt(2))