|x-1|=1

Lösung

∣ x - 1 ∣ = 1

x = 0 or x = 2

Schritte zur Lösung

∣ x - 1 ∣ = 1

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

x - 1 = - 1 or x - 1 = 1

x - 1 = - 1 or x - 1 = 1

x = 0 or x = 2

4 x^{2} + 4 x + 11 = 0

f a c t or x^{2} - x y - 5 x + 5 y

9 x + 4 \leq 103

x^{2} - 4 x - 5 \geq 0

2 x + 2 \leq 8 or 4 x + 1 > - 11