8x^2y+y^'=10x^2

Lösung

8 x^{2} y + y^{^{'}} = 10 x^{2}

y = \frac{e ^{\frac{- 8 x ^{3} + c _{1}}{3}}}{4} + \frac{5}{4}

Schritte zur Lösung

8 x^{2} y + y^{'} (x) = 10 x^{2}

Solve separable ODE:

y = \frac{e ^{\frac{- 8 x ^{3} + c _{1}}{3}}}{4} + \frac{5}{4}

y = \frac{e ^{\frac{- 8 x ^{3} + c _{1}}{3}}}{4} + \frac{5}{4}

d er i v a t i v e 4 x^{3} - 33 x^{2} + 84 x - 60

\frac{d}{d x} (2 x 16 - x^{2})

\frac{\partial}{\partial x} (2 x^{2} + y^{3})

d er i v a t i v e f (x) = \frac{2 x ^{\frac{3}{2}} - x ^{2} + 4}{x}

d er i v a t i v e \frac{500}{12 + 5 e ^{- 0.5 t}}