derivative of sqrt(x^2-4x-3)

解答

\frac{d}{d x} (x^{2} - 4 x - 3)

\frac{x - 2}{x ^{2} - 4 x - 3}

求解步骤

\frac{d}{d x} (x^{2} - 4 x - 3)

使用连锁律:

\frac{1}{2 x ^{2} - 4 x - 3} \frac{d}{d x} (x^{2} - 4 x - 3)

= \frac{1}{2 x ^{2} - 4 x - 3} \frac{d}{d x} (x^{2} - 4 x - 3)

\frac{d}{d x} (x^{2} - 4 x - 3) = 2 x - 4

= \frac{1}{2 x ^{2} - 4 x - 3} (2 x - 4)

化简

\frac{1}{2 x ^{2} - 4 x - 3} (2 x - 4) : \frac{x - 2}{x ^{2} - 4 x - 3}

= \frac{x - 2}{x ^{2} - 4 x - 3}

d er i v a t i v e \frac{x ^{2} + 2 x}{( x + 1 ) ^{2}}

\frac{\partial}{\partial h} (2 π r^{2} + 2 π r h)

a re a f (x) = x^{5} + 2, g (x) = x + 2

d er i v a t i v e y = e^{x} ln (x)

\frac{\partial}{\partial x} (20 - 2 x + 1.5 - y + 3 a)