(dy)/(dx)=(sqrt(y^2-9))

解答

\frac{d y}{d x} = (y^{2} - 9)

y = \frac{3}{2 e ^{x + c_{1}}} + \frac{3 e ^{x + c_{1}}}{2}

求解步骤

\frac{d y}{d x} = (y^{2} - 9)

求解可分离方程:

y = \frac{3}{2 e ^{x + c_{1}}} + \frac{3 e ^{x + c_{1}}}{2}

y = \frac{3}{2 e ^{x + c_{1}}} + \frac{3 e ^{x + c_{1}}}{2}

\frac{\partial}{\partial x} (e^{- 5 t} cos (π x))

d er i v a t i v e f (x) = x^{2} cos^{2} (x at x) = - 2

\int_{- 1}^{0} 20 \frac{e ^{\frac{1}{x}}}{x ^{3}} d x

\frac{d}{d x} (\frac{( a x + b )}{( c x + d )})

\int \frac{7}{3 + 7 x ^{2}} d x