derivative of Acos(x+Bsin(x))

Lösung

\frac{d}{d x} (A cos (x) + B sin (x))

- A sin (x) + B cos (x)

Schritte zur Lösung

\frac{d}{d x} (A cos (x) + B sin (x))

Behandle

A, B

als Konstanten

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (A cos (x)) + \frac{d}{d x} (B sin (x))

\frac{d}{d x} (A cos (x)) = - A sin (x)

\frac{d}{d x} (B sin (x)) = B cos (x)

= - A sin (x) + B cos (x)

\int_{- 1}^{6} - x^{2} + 5 x + 6 d x

a re a y = \frac{1}{2} x, y = \frac{6}{x}

\frac{d}{d x} (6 x^{5} ln (x) + x^{5})

x \to 0 lim (\frac{1 - cos ( 4 x )}{x})

\frac{d}{d x} (3 (4 e^{2 x} x + 4 e^{2 x}))