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受欢迎的微积分 >

integral of (x^{11})/(sqrt(2x^6+2))

解答

\int \frac{x ^{11}}{2 x ^{6} + 2} d x

解答

\frac{1}{3 2} (\frac{1}{3} (x^{6} + 1)^{\frac{3}{2}} - x^{6} + 1) + C

求解步骤

\int \frac{x ^{11}}{2 x ^{6} + 2} d x

\frac{x ^{11}}{2 x ^{6} + 2} = \frac{1}{2} \frac{x ^{11}}{x ^{6} + 1}

= \int \frac{1}{2} \cdot \frac{x ^{11}}{x ^{6} + 1} d x

提出常数:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{x ^{11}}{x ^{6} + 1} d x

使用换元积分法

= \frac{1}{2} \cdot \int \frac{u ^{2} - 1}{3} d u

提出常数:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \frac{1}{3} \cdot \int u^{2} - 1 d u

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} \cdot \frac{1}{3} (\int u^{2} d u - \int 1 d u)

\int u^{2} d u = \frac{u ^{3}}{3}

\int 1 d u = u

= \frac{1}{2} \cdot \frac{1}{3} (\frac{u ^{3}}{3} - u)

u = x^{6} + 1

代回

= \frac{1}{2} \cdot \frac{1}{3} (\frac{( x ^{6} + 1 ) ^{3}}{3} - x^{6} + 1)

化简

\frac{1}{2} \cdot \frac{1}{3} (\frac{( x ^{6} + 1 ) ^{3}}{3} - x^{6} + 1) : \frac{1}{3 2} (\frac{1}{3} (x^{6} + 1)^{\frac{3}{2}} - x^{6} + 1)

= \frac{1}{3 2} (\frac{1}{3} (x^{6} + 1)^{\frac{3}{2}} - x^{6} + 1)

解答补常数

= \frac{1}{3 2} (\frac{1}{3} (x^{6} + 1)^{\frac{3}{2}} - x^{6} + 1) + C

作图

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