derivative of-2x^5+1/(2x^2)

Lösung

\frac{d}{d x} (- 2 x^{5} + \frac{1}{2 x ^{2}})

- 10 x^{4} - \frac{1}{x ^{3}}

Schritte zur Lösung

\frac{d}{d x} (- 2 x^{5} + \frac{1}{2 x ^{2}})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 x^{5}) + \frac{d}{d x} (\frac{1}{2 x ^{2}})

\frac{d}{d x} (2 x^{5}) = 10 x^{4}

\frac{d}{d x} (\frac{1}{2 x ^{2}}) = - \frac{1}{x ^{3}}

= - 10 x^{4} - \frac{1}{x ^{3}}

y^{^{''}} + 25 y = - 50 sin (5 t)

\frac{d}{d x} (1 - (1 + \frac{x}{200}) e^{- \frac{x}{200}})

\int \frac{cos ^{2} ( x )}{4 + sin ( 2 x )} d x

\int_{1}^{2} \frac{x ^{2} + 1}{x} d x

t y^{^{'}} + t y = 1 - y