What is the derivative of (3x+4/(3x-4)) ?

The derivative of (3x+4/(3x-4)) is -(24)/((3x-4)^2)

What is the first derivative of (3x+4/(3x-4)) ?

The first derivative of (3x+4/(3x-4)) is -(24)/((3x-4)^2)

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\frac{d}{d x} (\frac{3 x + 4}{3 x - 4})

- \frac{24}{( 3 x - 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{3 x + 4}{3 x - 4})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 3 x + 4 ) ( 3 x - 4 ) - \frac{d}{d x} ( 3 x - 4 ) ( 3 x + 4 )}{( 3 x - 4 ) ^{2}}

\frac{d}{d x} (3 x + 4) = 3

\frac{d}{d x} (3 x - 4) = 3

= \frac{3 ( 3 x - 4 ) - 3 ( 3 x + 4 )}{( 3 x - 4 ) ^{2}}

Simplify

\frac{3 ( 3 x - 4 ) - 3 ( 3 x + 4 )}{( 3 x - 4 ) ^{2}} : - \frac{24}{( 3 x - 4 ) ^{2}}

= - \frac{24}{( 3 x - 4 ) ^{2}}

y^{2} = x^{2} (x + 1), (3, 6)

\int x^{l n (x)} d x

f (x) = x^{2} - 3 x, at x = - 2

1 - \frac{1}{x}

y^{'} = - \frac{2 y}{x} + 4 x

What is the derivative of (3x+4/(3x-4)) ?
The derivative of (3x+4/(3x-4)) is -(24)/((3x-4)^2)
What is the first derivative of (3x+4/(3x-4)) ?
The first derivative of (3x+4/(3x-4)) is -(24)/((3x-4)^2)