derivative f(3)= 1/x+(x^2-1)^3

Lösung

ableitung von

f (3) = \frac{1}{x} + (x^{2} - 1)^{3}

- \frac{1}{x ^{2}} + 6 x (x^{2} - 1)^{2}

Schritte zur Lösung

\frac{d}{d x} (\frac{1}{x} + (x^{2} - 1)^{3})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{x}) + \frac{d}{d x} ((x^{2} - 1)^{3})

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

\frac{d}{d x} ((x^{2} - 1)^{3}) = 6 x (x^{2} - 1)^{2}

= - \frac{1}{x ^{2}} + 6 x (x^{2} - 1)^{2}

x \to 9 lim (4 - x + 7)

x \to 0 + lim ((e^{a x} + x)^{\frac{1}{x}})

\frac{\partial}{\partial x} (\frac{y}{x - y})

\int_{1}^{\infty} x e^{- 7 x} d x

y^{^{'}} + 4 y = 6 e^{- 3 t}