integral from 0 to 1 of ln(4-2x)

Lösung

\int_{0}^{1} ln (4 - 2 x) d x

3 ln (2) - 1

Dezimale

1.07944 \dots

Schritte zur Lösung

\int_{0}^{1} ln (4 - 2 x) d x

Wende die partielle Integration an

= [x ln (4 - 2 x) - \int - \frac{x}{2 - x} d x]_{0}^{1}

\int - \frac{x}{2 - x} d x = 2 ln ∣ 2 - x ∣ + x

= [x ln (4 - 2 x) - (2 ln ∣ 2 - x ∣ + x)]_{0}^{1}

Vereinfache

= [x ln (4 - 2 x) - 2 ln ∣ 2 - x ∣ - x]_{0}^{1}

Berechne die Grenzen:

3 ln (2) - 1

= 3 ln (2) - 1

\int \frac{1}{x ( 5 x )} d x

\int x e^{- 1} d x

a re a y = 1 + 3 x, x = 0, x = 8, y = 0

\frac{d}{d x} (\frac{2 x ^{2} - 1}{( x - 1 ) ^{2}})

\frac{\partial}{\partial x} (x^{8} + 2^{y} + x^{y})