What is the limit as x approaches 0 of x^2*sin(1/(x^2)) ?

The limit as x approaches 0 of x^2*sin(1/(x^2)) is 0

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limit as x approaches 0 of x^2*sin(1/(x^2))

x \to 0 lim (x^{2} \cdot sin (\frac{1}{x ^{2}}))

0

Solution steps

x \to 0 lim (x^{2} sin (\frac{1}{x ^{2}}))

Apply the Squeeze Theorem:

0

= 0

\int sin^{5} (d) x d x

d er i v a t i v e tan (θ)

\frac{\partial}{\partial x} (z)

a re a - x^{3} + x^{2} + 16 x, 4 x, 0, 4

t an g e n t f (x) = (4 x + 5)^{4}, at x = - 1

What is the limit as x approaches 0 of x^2*sin(1/(x^2)) ?
The limit as x approaches 0 of x^2*sin(1/(x^2)) is 0