y^{''}+2y^'+y=x^2

Lösung

y^{^{''}} + 2 y^{^{'}} + y = x^{2}

y = c_{1} e^{- x} + c_{2} x e^{- x} + x^{2} - 4 x + 6

Schritte zur Lösung

y^{''} (x) + 2 y^{'} (x) + y = x^{2}

Solve linear ODE:

y = c_{1} e^{- x} + c_{2} x e^{- x} + x^{2} - 4 x + 6

y = c_{1} e^{- x} + c_{2} x e^{- x} + x^{2} - 4 x + 6

t an g e n t y = \frac{2 x + 3}{3 x - 2}

\int 9 cos (x) + 5 d x

\frac{\partial}{\partial x} (x^{0.1} y^{0.9})

x \to 0 lim (\frac{sin ( 4 x ^{2} )}{x})

\frac{\partial}{\partial x} (x \cdot y^{2} \cdot z^{3})