(\partial)/(\partial y)(y-cos(y))

Lösung

\frac{\partial}{\partial y} (y - cos (y))

1 + sin (y)

Schritte zur Lösung

\frac{\partial}{\partial y} (y - cos (y))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (y) - \frac{\partial}{\partial y} (cos (y))

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (cos (y)) = - sin (y)

= 1 - (- sin (y))

Vereinfache

= 1 + sin (y)

d er i v a t i v e f (x) = (x + 2)^{x}

\int 9 + 8 x - x^{2} d x

x \to 2 lim (3 x + 5)

\int cos^{5} (3 x) sin^{4} (3 x) d x

\int_{1}^{2} w^{2} ln (w) d w