What is the derivative of 2x^{-2} ?

The derivative of 2x^{-2} is -4/(x^3)

What is the first derivative of 2x^{-2} ?

The first derivative of 2x^{-2} is -4/(x^3)

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\frac{d}{d x} (2 x^{- 2})

- \frac{4}{x ^{3}}

Solution steps

\frac{d}{d x} (2 x^{- 2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 (- 2 x^{- 2 - 1})

Simplify

2 (- 2 x^{- 2 - 1}) : - \frac{4}{x ^{3}}

= - \frac{4}{x ^{3}}

y^{^{''}} - 8 y^{^{'}} + 20 y = 0

\int_{1}^{2} x 5^{(x^{2})} d x

x \to 0 lim (\frac{3 x ^{2} - 2 x}{x})

\int \frac{e ^{2 x} - 6 e ^{x}}{e ^{2 x} + 11} d x

t an g e n t f (x) = 20 x + 5

What is the derivative of 2x^{-2} ?
The derivative of 2x^{-2} is -4/(x^3)
What is the first derivative of 2x^{-2} ?
The first derivative of 2x^{-2} is -4/(x^3)