derivative f(x)=(2x-8)4(x^2+x+1)5

Lösung

ableitung von

f (x) = (2 x - 8) 4 (x^{2} + x + 1) 5

20 (6 x^{2} - 12 x - 6)

Schritte zur Lösung

\frac{d}{d x} ((2 x - 8) \cdot 4 (x^{2} + x + 1) \cdot 5)

Vereinfache

(2 x - 8) \cdot 4 (x^{2} + x + 1) \cdot 5 : 20 (2 x - 8) (x^{2} + x + 1)

= \frac{d}{d x} (20 (2 x - 8) (x^{2} + x + 1))

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= 20 \frac{d}{d x} ((2 x - 8) (x^{2} + x + 1))

Wende die Produktregel an:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 2 x - 8, g = x^{2} + x + 1

= 20 (\frac{d}{d x} (2 x - 8) (x^{2} + x + 1) + \frac{d}{d x} (x^{2} + x + 1) (2 x - 8))

\frac{d}{d x} (2 x - 8) = 2

\frac{d}{d x} (x^{2} + x + 1) = 2 x + 1

= 20 (2 (x^{2} + x + 1) + (2 x + 1) (2 x - 8))

Multipliziere aus

2 (x^{2} + x + 1) + (2 x + 1) (2 x - 8) : 6 x^{2} - 12 x - 6

= 20 (6 x^{2} - 12 x - 6)

in v erse l a pl a ce \frac{s + 2}{s ^{2} - s - 12}

x \to 0 lim (3 x^{7 x})

\int \frac{x ^{2} + 24 x - 16}{x ^{3} - 16 x} d x

d er i v a t i v e \frac{6}{7 t ^{4}}

x \to - 2 lim (\frac{3}{( x + 2 )})