integral of-0.2x^2+12x

Lösung

\int - 0.2 x^{2} + 12 x d x

- 0.06666 \dots x^{3} + 6 x^{2} + C

Schritte zur Lösung

\int - 0.2 x^{2} + 12 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 0.2 x^{2} d x + \int 12 x d x

\int 0.2 x^{2} d x = 0.06666 \dots x^{3}

\int 12 x d x = 6 x^{2}

= - 0.06666 \dots x^{3} + 6 x^{2}

Füge eine Konstante zur Lösung hinzu

= - 0.06666 \dots x^{3} + 6 x^{2} + C

\int 4 x^{4} + x^{2} d x

d er i v a t i v e f (x) = \frac{4}{( 3 x ) ^{- 2}}

\int \frac{5}{x ^{- 1} + 5} d x

x \to \infty lim (\frac{1}{x} - 3)

\frac{d}{d x} (\frac{7 x ^{2}}{x})