y^'=(x-2)/(y+1)

Lösung

y^{^{'}} = \frac{x - 2}{y + 1}

y = - 1 + x^{2} - 4 x + c_{1} + 1, y = - x^{2} - 4 x + c_{1} + 1 - 1

Schritte zur Lösung

y^{'} (x) = \frac{x - 2}{y + 1}

Solve separable ODE:

y = - 1 + x^{2} - 4 x + c_{1} + 1, y = - x^{2} - 4 x + c_{1} + 1 - 1

y = - 1 + x^{2} - 4 x + c_{1} + 1, y = - x^{2} - 4 x + c_{1} + 1 - 1

\int - ∣ x ∣^{2} d x

\int_{0}^{1} 4 ln (x) d x

s l o p e \frac{d}{d x} (\frac{5}{4 x}) - \frac{7}{4}

\int \frac{( arctan ( x ) ) ^{3}}{1 + x ^{2}} d x

\frac{\partial}{\partial x} (\frac{x}{x ^{2} + ( y - 1 ) ^{2}})