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Beliebt Rechnen >

y^'=-2y+t,y(0)=-5

Lösung

y^{^{'}} = - 2 y + t, y (0) = - 5

Lösung

y = \frac{2 t - 1}{4} - \frac{19}{4 e ^{2 t}}

Schritte zur Lösung

y^{'} (t) = - 2 y + t

Solve linear ODE:

y = \frac{2 t - 1}{4} - \frac{19}{4 e ^{2 t}}

y = \frac{2 t - 1}{4} - \frac{19}{4 e ^{2 t}}

Graph

Beliebte Beispiele

integral of 1/(y^2-3y+2)

\int \frac{1}{y ^{2} - 3 y + 2} d y

integral of (x^2+3x+1)

\int (x^{2} + 3 x + 1) d x

(dy)/(dx)+(x^2-1)y=-xy^6

\frac{d y}{d x} + (x^{2} - 1) y = - x y^{6}

(\partial)/(\partial y)(arctan(yz))

\frac{\partial}{\partial y} (arctan (yz))

e^{-x}(y^'-y)=y^2

e^{- x} (y^{^{'}} - y) = y^{2}