y^{''}+8y^'+25y=0,y(0)=-3,y^'(0)=1

Lösung

y^{^{''}} + 8 y^{^{'}} + 25 y = 0, y (0) = - 3, y^{^{'}} (0) = 1

y = e^{- 4 t} (- 3 cos (3 t) - \frac{11}{3} sin (3 t))

Schritte zur Lösung

y^{''} (t) + 8 y^{'} (t) + 25 y = 0

Solve linear ODE:

y = e^{- 4 t} (- 3 cos (3 t) - \frac{11}{3} sin (3 t))

y = e^{- 4 t} (- 3 cos (3 t) - \frac{11}{3} sin (3 t))

\int_{- 5}^{3} ∣ x ∣ + 1 d x

n = 2 \sum \infty \frac{3}{6 ^{n}}

x \to 0 lim (e^{x} cos (5 x))

81 y^{^{''}} + 72 y^{^{'}} + 16 y = 0, y (0) = 5, y^{^{'}} (0) = - 1

l a pl a ce t r an s f or m e^{\frac{2 t}{1}}