laplacetransform e^{(2t)/1}

Lösung

laplace transformation

e^{\frac{2 t}{1}}

\frac{1}{s - 2}

Schritte zur Lösung

L {e^{\frac{2 t}{1}}}

Wende Laplace-Transformationstabelle an:

L {e^{a t}} = \frac{1}{s - a}

L {e^{\frac{2}{1} t}} = \frac{1}{s - \frac{2}{1}}

= \frac{1}{s - \frac{2}{1}}

= \frac{1}{s - 2}

in v erse l a pl a ce \frac{6 s ^{2}}{s ^{2} ( s ^{2} + 16 )}

\frac{\partial}{\partial x} (\frac{3 x - 5}{2 x + 4})

x \to 0 + lim (\frac{14 x ^{3} + 15 x}{x})

\int - 4 sin (4 t) d t

\frac{d y}{d x} = 6 e^{x}