(dy)/(dx)+4xy^3=0

Lösung

\frac{d y}{d x} + 4 x y^{3} = 0

y = - \frac{1}{2 ( - 2 x ^{2} + c _{1} )}, y = - - \frac{1}{2 ( - 2 x ^{2} + c _{1} )}

Schritte zur Lösung

\frac{d y}{d x} + 4 x y^{3} = 0

Solve separable ODE:

y = - \frac{1}{2 ( - 2 x ^{2} + c _{1} )}, y = - - \frac{1}{2 ( - 2 x ^{2} + c _{1} )}

y = - \frac{1}{2 ( - 2 x ^{2} + c _{1} )}, y = - - \frac{1}{2 ( - 2 x ^{2} + c _{1} )}

d er i v a t i v e f (x) = (- 16 x^{2} + 36)^{2}

\frac{d}{d x} (arctan (tanh (x)))

\int \frac{2 x ^{3} + 1}{x ^{2} + x - 6} d x

\int \frac{1}{2 x ^{2} - 4 x + 6} d x

\int_{0}^{1} 2 π x (33 - 33 x) d x