derivative sqrt(7x+8)

Lösung

ableitung von

7 x + 8

\frac{7}{2 7 x + 8}

Schritte zur Lösung

\frac{d}{d x} (7 x + 8)

Wende die Kettenregel an:

\frac{1}{2 7 x + 8} \frac{d}{d x} (7 x + 8)

= \frac{1}{2 7 x + 8} \frac{d}{d x} (7 x + 8)

\frac{d}{d x} (7 x + 8) = 7

= \frac{1}{2 7 x + 8} \cdot 7

Vereinfache

\frac{1}{2 7 x + 8} \cdot 7 : \frac{7}{2 7 x + 8}

= \frac{7}{2 7 x + 8}

\int \frac{3}{( 3 x + 4 ) ln ( 3 x + 4 )} d x

x \to 0 lim (sin (3 x) cot (x))

x \to - 7 + lim (\frac{- x ^{2}}{x + 7})

x \to 1 lim (\frac{- 2 x ^{2}}{x - 1})

\int lo g_{e} (x^{2} + 1 - x) d x