fläche f(x)=3+2x-x^2,g(x)=x^2-4x+3

Lösung

fläche

f (x) = 3 + 2 x - x^{2}, g (x) = x^{2} - 4 x + 3

9

Schritte zur Lösung

Wenden Sie die Flächenformel an:

\int_{0}^{3} 3 + 2 x - x^{2} - (x^{2} - 4 x + 3) d x

Löse

\int_{0}^{3} 3 + 2 x - x^{2} - (x^{2} - 4 x + 3) d x : 9

Die Fläche ist:

= 9

a re a y = x, y = \frac{1}{4} x, x = 25

t an g e n t f (x) = - x^{3}

\frac{\partial}{\partial y} (\frac{1}{2} sin (2 x - y))

\int_{5}^{\infty} x e^{- 2 x} d x

\int 3 e^{x} + 8 x^{3} + 4 x d x