derivative of ln(4x+3)

解答

\frac{d}{d x} (ln (4 x + 3))

\frac{4}{4 x + 3}

求解步骤

\frac{d}{d x} (ln (4 x + 3))

使用连锁律:

\frac{1}{4 x + 3} \frac{d}{d x} (4 x + 3)

= \frac{1}{4 x + 3} \frac{d}{d x} (4 x + 3)

\frac{d}{d x} (4 x + 3) = 4

= \frac{1}{4 x + 3} \cdot 4

化简

\frac{1}{4 x + 3} \cdot 4 : \frac{4}{4 x + 3}

= \frac{4}{4 x + 3}

\frac{d}{d x} (\frac{( x ^{2} - 1 ) ^{3}}{x ^{2} + 1})

d er i v a t i v e (8 x^{2} - 13 x) e^{x}

\frac{\partial}{\partial x} ((x - y) e^{- x^{2} - y^{2}})

y^{^{''}} - y^{^{'}} - 2 y = 8 e - t

f (x) = x^{\frac{1}{x}}