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Beliebt Rechnen >

xy^'+y=2xy^2,y(1)=-5

Lösung

x y^{^{'}} + y = 2 x y^{2}, y (1) = - 5

Lösung

y = - \frac{5}{x ( 10 ln ( x ) + 1 )}

Schritte zur Lösung

x y^{'} (x) + y = 2 x y^{2}

Solve Bernoulli ODE:

y = - \frac{5}{x ( 10 ln ( x ) + 1 )}

y = - \frac{5}{x ( 10 ln ( x ) + 1 )}

Graph

Beliebte Beispiele

(\partial)/(\partial x)(e^ysin(xy))

\frac{\partial}{\partial x} (e^{y} sin (x y))

derivative of (12x^2-x^4/((4-x^2)^2))

\frac{d}{d x} (\frac{12 x ^{2} - x ^{4}}{( 4 - x ^{2} ) ^{2}})

derivative f(x)=(x-3)(2x+4)

d er i v a t i v e f (x) = (x - 3) (2 x + 4)

y^{^{'}} = - \frac{1}{40} y

derivative 7e^{-x}

d er i v a t i v e 7 e^{- x}