derivative y=\sqrt[4]{sin(3x-2)}

Lösung

ableitung von

y = 4 sin (3 x - 2)

\frac{3 cos ( 3 x - 2 )}{4 sin ^{\frac{3}{4}} ( 3 x - 2 )}

Schritte zur Lösung

\frac{d}{d x} (4 sin (3 x - 2))

Wende die Kettenregel an:

\frac{1}{4 ( sin ( 3 x - 2 ) ) ^{\frac{3}{4}}} \frac{d}{d x} (sin (3 x - 2))

= \frac{1}{4 ( sin ( 3 x - 2 ) ) ^{\frac{3}{4}}} \frac{d}{d x} (sin (3 x - 2))

\frac{d}{d x} (sin (3 x - 2)) = cos (3 x - 2) \cdot 3

= \frac{1}{4 ( sin ( 3 x - 2 ) ) ^{\frac{3}{4}}} cos (3 x - 2) \cdot 3

Vereinfache

\frac{1}{4 sin ^{\frac{3}{4}} ( 3 x - 2 )} cos (3 x - 2) \cdot 3 : \frac{3 cos ( 3 x - 2 )}{4 sin ^{\frac{3}{4}} ( 3 x - 2 )}

= \frac{3 cos ( 3 x - 2 )}{4 sin ^{\frac{3}{4}} ( 3 x - 2 )}

\int csc^{2} (6 x + 3) d x

t an g e n t f (x) = (ln (x))^{3}

x \to π lim ((x - π) tan (\frac{x}{2}))

\frac{\partial}{\partial x} (x y + yz + zy)

n = 0 \sum \infty \frac{3 ^{n}}{5 ^{n}}