integral of 4x-x^3

Lösung

\int 4 x - x^{3} d x

2 x^{2} - \frac{x ^{4}}{4} + C

Schritte zur Lösung

\int 4 x - x^{3} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 x d x - \int x^{3} d x

\int 4 x d x = 2 x^{2}

\int x^{3} d x = \frac{x ^{4}}{4}

= 2 x^{2} - \frac{x ^{4}}{4}

Füge eine Konstante zur Lösung hinzu

= 2 x^{2} - \frac{x ^{4}}{4} + C

i = 1 \sum \infty (\frac{1}{2})^{i - 1}

y^{^{''}} - 3 y^{^{'}} = 2 e^{x} sin (2 x)

d er i v a t i v e f (x) = \frac{x - 7}{9 x ^{2} e ^{x}}

\frac{\partial}{\partial x} ((e^{x} - 3) sin (y))

d er i v a t i v e \frac{3}{x ^{2}} - 8 4 x