taylor [(z-1)^3(z+1)^2]

Lösung

taylor

[(z - 1)^{3} (z + 1)^{2}]

- 1 + z + 2 z^{2} - 2 z^{3} - z^{4}

Schritte zur Lösung

Apply the Taylor Formula

= - 1 + \frac{\frac{d}{d z} ( [ ( z - 1 ) ^{3} ( z + 1 ) ^{2} ] ) ( 0 )}{1 !} z + \frac{\frac{d ^{2}}{d z ^{2}} ( [ ( z - 1 ) ^{3} ( z + 1 ) ^{2} ] ) ( 0 )}{2 !} z^{2} + \frac{\frac{d ^{3}}{d z ^{3}} ( [ ( z - 1 ) ^{3} ( z + 1 ) ^{2} ] ) ( 0 )}{3 !} z^{3} + \dots

Evaluate Derivatives

= - 1 + \frac{1}{1 !} z + \frac{4}{2 !} z^{2} + \frac{- 12}{3 !} z^{3} + \frac{- 24}{4 !} z^{4}

Fasse zusammen

= - 1 + z + 2 z^{2} - 2 z^{3} - z^{4}

\frac{\partial}{\partial y} (y + (cos (x))^{2})

((\frac{1 + e ^{x}}{2})^{9})^{^{'}}

\frac{d}{d x} (5 5 x^{4})

\int 5 x tan^{2} (x) d x

\int 2 x e^{- 4 x} d x