斜率 (-5,-2),(3,-9)

解答

斜率

(- 5, - 2), (3, - 9)

m = - \frac{7}{8}

求解步骤

两点之间的斜率: 斜率

= \frac{y _{2} - y _{1}}{x _{2} - x _{1}}

(x_{1}, y_{1}) = (- 5, - 2), (x_{2}, y_{2}) = (3, - 9)

m = \frac{- 9 - ( - 2 )}{3 - ( - 5 )}

整理后得

m = - \frac{7}{8}

\int_{0}^{2} (10 x - 5 x^{2}) d x

\int \frac{1}{10 - 0.8 x} d x

y^{^{''}} - 10 y^{^{'}} + 25 y = 4 x e^{5 x}

\frac{\partial}{\partial x} (9 x e^{2 x y})

in v erse l a pl a ce \frac{s ^{2} + 2 s + 5}{s ^{2} ( s + 1 )}