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受欢迎的微积分 >

tangent (25x^3)/3+10x^2+4x-7

解答

切线

\frac{25 x ^{3}}{3} + 10 x^{2} + 4 x - 7

解答

y = (25 a_{0}^{2} + 20 a_{0} + 4) x - 25 a_{0}^{3} - 10 a_{0}^{2} + \frac{25 a _{0}^{3}}{3} - 7

求解步骤

计算在一般点

x = a_{0}

的切线

找到切点:

(a_{0}, \frac{25 a _{0}^{3}}{3} + 10 a_{0}^{2} + 4 a_{0} - 7)

计算

y = \frac{25 x ^{3}}{3} + 10 x^{2} + 4 x - 7

的斜率:

\frac{d y}{d x} = 25 x^{2} + 20 x + 4

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 25 a_{0}^{2} + 20 a_{0} + 4

找到斜率 m=

25 a_{0}^{2} + 20 a_{0} + 4

且穿过

(a_{0}, \frac{25 a _{0}^{3}}{3} + 10 a_{0}^{2} + 4 a_{0} - 7)

的直线:

y = (25 a_{0}^{2} + 20 a_{0} + 4) x - 25 a_{0}^{3} - 10 a_{0}^{2} + \frac{25 a _{0}^{3}}{3} - 7

y = (25 a_{0}^{2} + 20 a_{0} + 4) x - 25 a_{0}^{3} - 10 a_{0}^{2} + \frac{25 a _{0}^{3}}{3} - 7

作图

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