(\partial)/(\partial x)(7+ln(xy-9))

解答

\frac{\partial}{\partial x} (7 + ln (x y - 9))

\frac{y}{x y - 9}

求解步骤

\frac{\partial}{\partial x} (7 + ln (x y - 9))

将

y

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (7) + \frac{\partial}{\partial x} (ln (x y - 9))

\frac{\partial}{\partial x} (7) = 0

\frac{\partial}{\partial x} (ln (x y - 9)) = \frac{y}{y x - 9}

= 0 + \frac{y}{y x - 9}

化简

= \frac{y}{x y - 9}

\frac{d}{d y} (e^{x} cos (y))

\frac{\partial}{\partial x} (\frac{26}{( 2 + x ^{2} + y ^{2} )})

\int e^{x} \cdot 7 x d x

(u^{2} + u) d x + u^{2} (x d u + u d x) = 0

x \to 4 lim (e^{x} + 4 x)