(\partial)/(\partial y)(4x-2y+3)

Lösung

\frac{\partial}{\partial y} (4 x - 2 y + 3)

- 2

Schritte zur Lösung

\frac{\partial}{\partial y} (4 x - 2 y + 3)

Behandle

x

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (4 x) - \frac{\partial}{\partial y} (2 y) + \frac{\partial}{\partial y} (3)

\frac{\partial}{\partial y} (4 x) = 0

\frac{\partial}{\partial y} (2 y) = 2

\frac{\partial}{\partial y} (3) = 0

= 0 - 2 + 0

Vereinfache

= - 2

\frac{d}{d x} (2 π \cdot \frac{x}{9.8})

\frac{d}{d x} (- 7 e^{- x})

\frac{d}{d x} (\frac{x ^{4} - 2 x ^{2} + 5 x + 1}{x ^{4}})

xv \frac{d v}{d x} + v^{2} = 32 x

x \to 1 lim (\frac{x - 1}{∣ x - 1 ∣})