derivative 2xe^{x^2}

解

導関数

2 x e^{x^{2}}

2 (e^{x^{2}} + 2 e^{x^{2}} x^{2})

解答ステップ

\frac{d}{d x} (2 x e^{x^{2}})

定数を除去:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x e^{x^{2}})

積の法則を適用:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{x^{2}}

= 2 (\frac{d x}{d x} e^{x^{2}} + \frac{d}{d x} (e^{x^{2}}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x^{2}}) = e^{x^{2}} \cdot 2 x

= 2 (1 \cdot e^{x^{2}} + e^{x^{2}} \cdot 2 xx)

簡素化

2 (1 \cdot e^{x^{2}} + e^{x^{2}} \cdot 2 xx) : 2 (e^{x^{2}} + 2 e^{x^{2}} x^{2})

= 2 (e^{x^{2}} + 2 e^{x^{2}} x^{2})