derivative of 10sin(2x+15cos(2x)+100)

Lösung

\frac{d}{d x} (10 sin (2 x) + 15 cos (2 x) + 100)

20 cos (2 x) - 30 sin (2 x)

Schritte zur Lösung

\frac{d}{d x} (10 sin (2 x) + 15 cos (2 x) + 100)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (10 sin (2 x)) + \frac{d}{d x} (15 cos (2 x)) + \frac{d}{d x} (100)

\frac{d}{d x} (10 sin (2 x)) = 20 cos (2 x)

\frac{d}{d x} (15 cos (2 x)) = - 30 sin (2 x)

\frac{d}{d x} (100) = 0

= 20 cos (2 x) - 30 sin (2 x) + 0

Vereinfache

= 20 cos (2 x) - 30 sin (2 x)

\frac{d}{d x} (arctan (\frac{x}{1 + 1 - x ^{2}}))

a re a y = 7 x, y = x^{2}

\int \frac{3 ^{t a n (5 x)}}{cos ^{2} ( 5 x )} d x

d er i v a t i v e \frac{( t ^{3} + t )}{t ^{4} - 2}

x \to 2 + lim (f (x))