derivative 2cos(2x)+2sin(2x)+4x

解答

导数

2 cos (2 x) + 2 sin (2 x) + 4 x

- 4 sin (2 x) + 4 cos (2 x) + 4

求解步骤

\frac{d}{d x} (2 cos (2 x) + 2 sin (2 x) + 4 x)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 cos (2 x)) + \frac{d}{d x} (2 sin (2 x)) + \frac{d}{d x} (4 x)

\frac{d}{d x} (2 cos (2 x)) = - 4 sin (2 x)

\frac{d}{d x} (2 sin (2 x)) = 4 cos (2 x)

\frac{d}{d x} (4 x) = 4

= - 4 sin (2 x) + 4 cos (2 x) + 4

\int (2 + x) d x

\frac{d}{d x} (\frac{- 2}{3 x + 7})

n = 0 \sum \infty \frac{n !}{( 2 n ) !}

d er i v a t i v e y = ln (ln (x))

t an g e n t f (x) = x^{3} - 1.5 x^{2} - 90 x - 22