y^'=(4x+y)^2

Lösung

y^{^{'}} = (4 x + y)^{2}

y = 2 tan (2 x + c_{1}) - 4 x

Schritte zur Lösung

y^{'} (x) = (4 x + y)^{2}

Solve using substitution:

y = 2 tan (2 x + c_{1}) - 4 x

y = 2 tan (2 x + c_{1}) - 4 x

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