What is the tangent of f(x)=2x^4,\at x=-2 ?

The tangent of f(x)=2x^4,\at x=-2 is y=-64x-96

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tangent of f(x)=2x^4,\at x=-2

tangent of

f (x) = 2 x^{4}, at x = - 2

y = - 64 x - 96

Solution steps

Find the tangent point:

(- 2, 32)

Find the slope of

f (x) = 2 x^{4} : \frac{df ( x )}{d x} = 8 x^{3}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 64

Find the line with slope m=

- 64

and passing through

(- 2, 32) : y = - 64 x - 96

y = - 64 x - 96

\int cos (x) ln (x) d x

\frac{\partial}{\partial x} (x cos (y) + y)

\frac{d}{d x} (e^{\frac{x}{8}} cos (\frac{x}{8}))

x \to 0 lim (sin (x) + 1)

\int \frac{x ^{2} + 4}{3 x ^{2} + 4 x ^{2} - 4 x} d x

What is the tangent of f(x)=2x^4,\at x=-2 ?
The tangent of f(x)=2x^4,\at x=-2 is y=-64x-96