What is the derivative of-x^3+6x^2-9x ?

The derivative of-x^3+6x^2-9x is -3x^2+12x-9

What is the first derivative of-x^3+6x^2-9x ?

The first derivative of-x^3+6x^2-9x is -3x^2+12x-9

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\frac{d}{d x} (- x^{3} + 6 x^{2} - 9 x)

- 3 x^{2} + 12 x - 9

Solution steps

\frac{d}{d x} (- x^{3} + 6 x^{2} - 9 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{3}) + \frac{d}{d x} (6 x^{2}) - \frac{d}{d x} (9 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d}{d x} (9 x) = 9

= - 3 x^{2} + 12 x - 9

\int \frac{- 5}{x ^{2} + 16} d x

\int \frac{2 e ^{- \frac{6}{x ^{4}}}}{x ^{5}} d x

\frac{d ^{2} y}{d t ^{2}} - 8 \frac{d y}{d t} + 16 y = 0

t an g e n t f (x) = x^{3}, at x = 1

d er i v a t i v e y = ln (18 x^{2} - 5 x + 11)

What is the derivative of-x^3+6x^2-9x ?
The derivative of-x^3+6x^2-9x is -3x^2+12x-9
What is the first derivative of-x^3+6x^2-9x ?
The first derivative of-x^3+6x^2-9x is -3x^2+12x-9