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人気のある微分積分 >

integral from 3 to 4 of xsqrt(x-3)

解

\int_{3}^{4} x x - 3 d x

解

\frac{12}{5}

+1

十進法表記

2.4

解答ステップ

\int_{3}^{4} x x - 3 d x

u置換積分法を適用する

= \int_{0}^{1} (u + 3) u d u

拡張

(u + 3) u : u^{\frac{3}{2}} + 3 u

= \int_{0}^{1} u^{\frac{3}{2}} + 3 u d u

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} u^{\frac{3}{2}} d u + \int_{0}^{1} 3 u d u

\int_{0}^{1} u^{\frac{3}{2}} d u = \frac{2}{5}

\int_{0}^{1} 3 u d u = 2

= \frac{2}{5} + 2

簡素化

\frac{2}{5} + 2 : \frac{12}{5}

= \frac{12}{5}

グラフ

人気の例

tangent f(x)= 1/(x+9),\at x=-7

t an g e n t f (x) = \frac{1}{x + 9}, at x = - 7

(\partial)/(\partial x)(3ye^{4xy}+8x)

\frac{\partial}{\partial x} (3 y e^{4 x y} + 8 x)

integral of 3/(12x-1)

\int \frac{3}{12 x - 1} d x

f (x) = \frac{x}{e ^{x}}

(\partial)/(\partial x)(x^2-xy+8y^2)

\frac{\partial}{\partial x} (x^{2} - x y + 8 y^{2})