integral of log_{2}(x)

解答

\int lo g_{2} (x) d x

x lo g_{2} (x) - \frac{1}{ln ( 2 )} x + C

求解步骤

\int lo g_{2} (x) d x

使用分布积分法

= x lo g_{2} (x) - \int \frac{1}{ln ( 2 )} d x

\int \frac{1}{ln ( 2 )} d x = \frac{1}{ln ( 2 )} x

= x lo g_{2} (x) - \frac{1}{ln ( 2 )} x

解答补常数

= x lo g_{2} (x) - \frac{1}{ln ( 2 )} x + C

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