integral from 3 to x^3 of t^4

解答

\int_{3}^{x^{3}} t^{4} d t

\frac{x ^{15} - 243}{5}

求解步骤

\int_{3}^{x^{3}} t^{4} d t

使用幂法则

= [\frac{t ^{5}}{5}]_{3}^{x^{3}}

带入上下限计算后得:

\frac{x ^{15}}{5} - \frac{243}{5}

= \frac{x ^{15}}{5} - \frac{243}{5}

化简

= \frac{x ^{15} - 243}{5}

\int_{0}^{2} 2 x - x^{2} d x

\frac{\partial}{\partial y} (\frac{( 2 x + y )}{z})

t an g e n t f (x) = \frac{4}{x}, (4, 2)

d er i v a t i v e 4 e^{4 x}

d er i v a t i v e 6 x + 5