derivative (10x+20)/x

Lösung

ableitung von

\frac{10 x + 20}{x}

- \frac{20}{x ^{2}}

Schritte zur Lösung

\frac{d}{d x} (\frac{10 x + 20}{x})

Wende die Quotientenregel an:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 10 x + 20 ) x - \frac{d x}{d x} ( 10 x + 20 )}{x ^{2}}

\frac{d}{d x} (10 x + 20) = 10

\frac{d x}{d x} = 1

= \frac{10 x - 1 \cdot ( 10 x + 20 )}{x ^{2}}

Vereinfache

\frac{10 x - 1 \cdot ( 10 x + 20 )}{x ^{2}} : - \frac{20}{x ^{2}}

= - \frac{20}{x ^{2}}

\int tan^{3} (6 x) sec (6 x) d x

\int y^{2} - x^{2} d x

x \to - 2 lim (25 - 5 x)

d er i v a t i v e f (x) = x^{\frac{4}{3}} - 4 x^{\frac{1}{3}} + 1

\frac{d}{d x} (x^{2} 5 - x)