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人気のある微分積分 >

integral from-4 to 0 of (1+sqrt(16-x^2))

解

\int_{- 4}^{0} (1 + 16 - x^{2}) d x

解

4 + 4 π

+1

十進法表記

16.56637 \dots

解答ステップ

\int_{- 4}^{0} 1 + 16 - x^{2} d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 4}^{0} 1 d x + \int_{- 4}^{0} 16 - x^{2} d x

\int_{- 4}^{0} 1 d x = 4

\int_{- 4}^{0} 16 - x^{2} d x = 4 π

= 4 + 4 π

グラフ

人気の例

integral of t^2sqrt(13t-1)

\int t^{2} 13 t - 1 d t

derivative f(x)=(4/x)+(1/(5x^3+2x))

d er i v a t i v e f (x) = (\frac{4}{x}) + (\frac{1}{5 x ^{3} + 2 x})

integral from 0 to pi/2 of sec^2(x/2)

\int_{0}^{\frac{π}{2}} sec^{2} (\frac{x}{2}) d x

x y^{^{'}} - 2 y = 0

y^{^{'}} + y = 4 x