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人気のある微分積分 >

tangent f(x)=(2x+4)^{1/5}

解

タンジェント

f (x) = (2 x + 4)^{\frac{1}{5}}

解

y = \frac{2}{5 ( 2 a _{0} + 4 ) ^{\frac{4}{5}}} x + (2 a_{0} + 4)^{\frac{1}{5}} - \frac{2 a _{0}}{5 ( 2 a _{0} + 4 ) ^{\frac{4}{5}}}

解答ステップ

一般的なポイントへの接線を計算する

x = a_{0}

接点を見つける:

(a_{0}, (2 a_{0} + 4)^{\frac{1}{5}})

以下の傾斜を見つける:

f (x) = (2 x + 4)^{\frac{1}{5}} : \frac{df ( x )}{d x} = \frac{2}{5 ( 2 x + 4 ) ^{\frac{4}{5}}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{2}{5 ( 2 a _{0} + 4 ) ^{\frac{4}{5}}}

傾斜m=

\frac{2}{5 ( 2 a _{0} + 4 ) ^{\frac{4}{5}}}

で通過する線を見つける

(a_{0}, (2 a_{0} + 4)^{\frac{1}{5}}) : y = \frac{2}{5 ( 2 a _{0} + 4 ) ^{\frac{4}{5}}} x + (2 a_{0} + 4)^{\frac{1}{5}} - \frac{2 a _{0}}{5 ( 2 a _{0} + 4 ) ^{\frac{4}{5}}}

y = \frac{2}{5 ( 2 a _{0} + 4 ) ^{\frac{4}{5}}} x + (2 a_{0} + 4)^{\frac{1}{5}} - \frac{2 a _{0}}{5 ( 2 a _{0} + 4 ) ^{\frac{4}{5}}}

グラフ

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