integral from 1 to 4 of (2-x^2)-(6-5x)

Lösung

\int_{1}^{4} (2 - x^{2}) - (6 - 5 x) d x

\frac{9}{2}

Dezimale

4.5

Schritte zur Lösung

\int_{1}^{4} 2 - x^{2} - (6 - 5 x) d x

Vereinfache

= \int_{1}^{4} - x^{2} + 5 x - 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{1}^{4} x^{2} d x + \int_{1}^{4} 5 x d x - \int_{1}^{4} 4 d x

\int_{1}^{4} x^{2} d x = 21

\int_{1}^{4} 5 x d x = \frac{75}{2}

\int_{1}^{4} 4 d x = 12

= - 21 + \frac{75}{2} - 12

Vereinfache

- 21 + \frac{75}{2} - 12 : \frac{9}{2}

= \frac{9}{2}

\frac{d}{d x} (\frac{3 x + 4}{7 x - 5})

t an g e n t (x^{2} - 24)^{6}

t an g e n t 5 x^{2} + 2 x, at x = 3

\int sin^{3} (4 θ) cos (4 θ) d θ

t an g e n t f (x) = x^{2} + 4