fläche sqrt(x-2),14-x,2

Lösung

fläche

x - 2, 14 - x, 2

\frac{19}{6}

Dezimale

3.16666 \dots

Schritte zur Lösung

Um die Schnittpunkte zu finden, löse

f_{i} (x) = f_{j} (x)

x - 2 = 14 - x : x = 11

x - 2 = 2 : x = 6

14 - x = 2 : x = 12

= \int_{6}^{11} ∣ f_{1} (x) - f_{3} (x) ∣ d x + \int_{11}^{12} ∣ f_{3} (x) - f_{2} (x) ∣ d x

= \int_{6}^{11} x - 2 - 2 d x + \int_{11}^{12} ∣ 2 - (14 - x) ∣ d x

\int_{6}^{11} x - 2 - 2 d x = \frac{8}{3}

\int_{11}^{12} ∣ 2 - (14 - x) ∣ d x = \frac{1}{2}

= \frac{8}{3} + \frac{1}{2}

Vereinfache

= \frac{19}{6}

\int (1 - x) cos (nπ x) d x

in v erse l a pl a ce \frac{5 s}{s ^{2} + 4}

\frac{\partial}{\partial y} (x y - x^{2} - y^{2})

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\int x e^{4 - x^{2}} d x