integral of e^{2x+4}-6x

Lösung

\int e^{2 x + 4} - 6 x d x

\frac{1}{2} e^{2 x + 4} - 3 x^{2} + C

Schritte zur Lösung

\int e^{2 x + 4} - 6 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int e^{2 x + 4} d x - \int 6 x d x

\int e^{2 x + 4} d x = \frac{1}{2} e^{2 x + 4}

\int 6 x d x = 3 x^{2}

= \frac{1}{2} e^{2 x + 4} - 3 x^{2}

Füge eine Konstante zur Lösung hinzu

= \frac{1}{2} e^{2 x + 4} - 3 x^{2} + C

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