1/y y^'=-1/x

Lösung

\frac{1}{y} y^{^{'}} = - \frac{1}{x}

y = \frac{c _{1}}{x}

Schritte zur Lösung

\frac{1}{y} y^{'} (x) = - \frac{1}{x}

Solve separable ODE:

y = \frac{c _{1}}{x}

y = \frac{c _{1}}{x}

y^{^{''}} + 3 y^{^{'}} + 2 y = sin^{2} (t)

y^{^{''}} + 14 y^{^{'}} + 50 y = 0

\int (\frac{x}{( x ^{2} + 1 ) ^{2}}) d x

x y^{^{'}} + y = 3 x y^{2}, y (1) = - 3

d er i v a t i v e 7 x