d/(dt)(3+3cos(t^3)-4sin(t^3))

Lösung

\frac{d}{d t} (3 + 3 cos (t^{3}) - 4 sin (t^{3}))

- 9 t^{2} sin (t^{3}) - 12 t^{2} cos (t^{3})

Schritte zur Lösung

\frac{d}{d t} (3 + 3 cos (t^{3}) - 4 sin (t^{3}))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (3) + \frac{d}{d t} (3 cos (t^{3})) - \frac{d}{d t} (4 sin (t^{3}))

\frac{d}{d t} (3) = 0

\frac{d}{d t} (3 cos (t^{3})) = - 9 t^{2} sin (t^{3})

\frac{d}{d t} (4 sin (t^{3})) = 12 t^{2} cos (t^{3})

= 0 - 9 t^{2} sin (t^{3}) - 12 t^{2} cos (t^{3})

Vereinfache

= - 9 t^{2} sin (t^{3}) - 12 t^{2} cos (t^{3})

d er i v a t i v e x^{- 10}

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